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309 lines
11 KiB
Python
309 lines
11 KiB
Python
from __future__ import print_function
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from string import ascii_lowercase, digits
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##################################
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StringName = u'PyJsConstantString%d_'
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NumberName = u'PyJsConstantNumber%d_'
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RegExpName = u'PyJsConstantRegExp%d_'
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##################################
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ALPHAS = set(ascii_lowercase + ascii_lowercase.upper())
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NUMS = set(digits)
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IDENTIFIER_START = ALPHAS.union(NUMS)
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ESCAPE_CHARS = {'n', '0', 'b', 'f', 'r', 't', 'v', '"', "'", '\\'}
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OCTAL = {'0', '1', '2', '3', '4', '5', '6', '7'}
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HEX = set('0123456789abcdefABCDEF')
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from utils import *
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IDENTIFIER_PART = IDENTIFIER_PART.union({'.'})
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def _is_cancelled(source, n):
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cancelled = False
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k = 0
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while True:
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k += 1
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if source[n - k] != '\\':
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break
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cancelled = not cancelled
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return cancelled
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def _ensure_regexp(source, n): #<- this function has to be improved
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'''returns True if regexp starts at n else returns False
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checks whether it is not a division '''
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markers = '(+~"\'=[%:?!*^|&-,;/\\'
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k = 0
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while True:
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k += 1
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if n - k < 0:
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return True
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char = source[n - k]
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if char in markers:
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return True
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if char != ' ' and char != '\n':
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break
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return False
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def parse_num(source, start, charset):
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"""Returns a first index>=start of chat not in charset"""
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while start < len(source) and source[start] in charset:
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start += 1
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return start
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def parse_exponent(source, start):
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"""returns end of exponential, raises SyntaxError if failed"""
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if not source[start] in {'e', 'E'}:
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if source[start] in IDENTIFIER_PART:
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raise SyntaxError('Invalid number literal!')
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return start
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start += 1
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if source[start] in {'-', '+'}:
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start += 1
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FOUND = False
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# we need at least one dig after exponent
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while source[start] in NUMS:
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FOUND = True
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start += 1
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if not FOUND or source[start] in IDENTIFIER_PART:
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raise SyntaxError('Invalid number literal!')
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return start
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def remove_constants(source):
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'''Replaces Strings and Regexp literals in the source code with
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identifiers and *removes comments*. Identifier is of the format:
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PyJsStringConst(String const number)_ - for Strings
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PyJsRegExpConst(RegExp const number)_ - for RegExps
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Returns dict which relates identifier and replaced constant.
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Removes single line and multiline comments from JavaScript source code
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Pseudo comments (inside strings) will not be removed.
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For example this line:
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var x = "/*PSEUDO COMMENT*/ TEXT //ANOTHER PSEUDO COMMENT"
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will be unaltered'''
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source = ' ' + source + '\n'
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comments = []
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inside_comment, single_comment = False, False
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inside_single, inside_double = False, False
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inside_regexp = False
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regexp_class_count = 0
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n = 0
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while n < len(source):
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char = source[n]
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if char == '"' and not (inside_comment or inside_single
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or inside_regexp):
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if not _is_cancelled(source, n):
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if inside_double:
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inside_double[1] = n + 1
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comments.append(inside_double)
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inside_double = False
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else:
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inside_double = [n, None, 0]
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elif char == "'" and not (inside_comment or inside_double
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or inside_regexp):
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if not _is_cancelled(source, n):
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if inside_single:
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inside_single[1] = n + 1
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comments.append(inside_single)
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inside_single = False
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else:
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inside_single = [n, None, 0]
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elif (inside_single or inside_double):
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if char in LINE_TERMINATOR:
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if _is_cancelled(source, n):
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if char == CR and source[n + 1] == LF:
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n += 1
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n += 1
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continue
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else:
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raise SyntaxError(
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'Invalid string literal. Line terminators must be escaped!'
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)
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else:
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if inside_comment:
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if single_comment:
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if char in LINE_TERMINATOR:
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inside_comment[1] = n
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comments.append(inside_comment)
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inside_comment = False
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single_comment = False
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else: # Multiline
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if char == '/' and source[n - 1] == '*':
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inside_comment[1] = n + 1
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comments.append(inside_comment)
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inside_comment = False
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elif inside_regexp:
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if not quiting_regexp:
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if char in LINE_TERMINATOR:
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raise SyntaxError(
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'Invalid regexp literal. Line terminators cant appear!'
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)
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if _is_cancelled(source, n):
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n += 1
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continue
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if char == '[':
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regexp_class_count += 1
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elif char == ']':
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regexp_class_count = max(regexp_class_count - 1, 0)
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elif char == '/' and not regexp_class_count:
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quiting_regexp = True
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else:
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if char not in IDENTIFIER_START:
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inside_regexp[1] = n
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comments.append(inside_regexp)
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inside_regexp = False
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elif char == '/' and source[n - 1] == '/':
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single_comment = True
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inside_comment = [n - 1, None, 1]
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elif char == '*' and source[n - 1] == '/':
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inside_comment = [n - 1, None, 1]
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elif char == '/' and source[n + 1] not in ('/', '*'):
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if not _ensure_regexp(source, n): #<- improve this one
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n += 1
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continue #Probably just a division
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quiting_regexp = False
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inside_regexp = [n, None, 2]
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elif not (inside_comment or inside_regexp):
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if (char in NUMS and
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source[n - 1] not in IDENTIFIER_PART) or char == '.':
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if char == '.':
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k = parse_num(source, n + 1, NUMS)
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if k == n + 1: # just a stupid dot...
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n += 1
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continue
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k = parse_exponent(source, k)
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elif char == '0' and source[n + 1] in {
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'x', 'X'
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}: #Hex number probably
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k = parse_num(source, n + 2, HEX)
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if k == n + 2 or source[k] in IDENTIFIER_PART:
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raise SyntaxError('Invalid hex literal!')
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else: #int or exp or flot or exp flot
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k = parse_num(source, n + 1, NUMS)
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if source[k] == '.':
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k = parse_num(source, k + 1, NUMS)
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k = parse_exponent(source, k)
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comments.append((n, k, 3))
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n = k
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continue
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n += 1
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res = ''
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start = 0
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count = 0
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constants = {}
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for end, next_start, typ in comments:
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res += source[start:end]
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start = next_start
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if typ == 0: # String
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name = StringName
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elif typ == 1: # comment
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continue
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elif typ == 2: # regexp
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name = RegExpName
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elif typ == 3: # number
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name = NumberName
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else:
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raise RuntimeError()
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res += ' ' + name % count + ' '
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constants[name % count] = source[end:next_start]
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count += 1
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res += source[start:]
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# remove this stupid white space
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for e in WHITE:
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res = res.replace(e, ' ')
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res = res.replace(CR + LF, '\n')
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for e in LINE_TERMINATOR:
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res = res.replace(e, '\n')
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return res.strip(), constants
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def recover_constants(py_source,
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replacements): #now has n^2 complexity. improve to n
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'''Converts identifiers representing Js constants to the PyJs constants
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PyJsNumberConst_1_ which has the true value of 5 will be converted to PyJsNumber(5)'''
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for identifier, value in replacements.iteritems():
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if identifier.startswith('PyJsConstantRegExp'):
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py_source = py_source.replace(identifier,
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'JsRegExp(%s)' % repr(value))
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elif identifier.startswith('PyJsConstantString'):
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py_source = py_source.replace(
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identifier, 'Js(u%s)' % unify_string_literals(value))
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else:
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py_source = py_source.replace(identifier, 'Js(%s)' % value)
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return py_source
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def unify_string_literals(js_string):
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"""this function parses the string just like javascript
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for example literal '\d' in JavaScript would be interpreted
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as 'd' - backslash would be ignored and in Pyhon this
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would be interpreted as '\\d' This function fixes this problem."""
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n = 0
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res = ''
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limit = len(js_string)
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while n < limit:
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char = js_string[n]
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if char == '\\':
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new, n = do_escape(js_string, n)
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res += new
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else:
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res += char
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n += 1
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return res
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def unify_regexp_literals(js):
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pass
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def do_escape(source, n):
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"""Its actually quite complicated to cover every case :)
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http://www.javascriptkit.com/jsref/escapesequence.shtml"""
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if not n + 1 < len(source):
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return '' # not possible here but can be possible in general case.
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if source[n + 1] in LINE_TERMINATOR:
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if source[n + 1] == CR and n + 2 < len(source) and source[n + 2] == LF:
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return source[n:n + 3], n + 3
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return source[n:n + 2], n + 2
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if source[n + 1] in ESCAPE_CHARS:
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return source[n:n + 2], n + 2
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if source[n + 1] in {'x', 'u'}:
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char, length = ('u', 4) if source[n + 1] == 'u' else ('x', 2)
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n += 2
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end = parse_num(source, n, HEX)
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if end - n < length:
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raise SyntaxError('Invalid escape sequence!')
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#if length==4:
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# return unichr(int(source[n:n+4], 16)), n+4 # <- this was a very bad way of solving this problem :)
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return source[n - 2:n + length], n + length
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if source[n + 1] in OCTAL:
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n += 1
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end = parse_num(source, n, OCTAL)
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end = min(end, n + 3) # cant be longer than 3
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# now the max allowed is 377 ( in octal) and 255 in decimal
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max_num = 255
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num = 0
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len_parsed = 0
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for e in source[n:end]:
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cand = 8 * num + int(e)
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if cand > max_num:
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break
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num = cand
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len_parsed += 1
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# we have to return in a different form because python may want to parse more...
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# for example '\777' will be parsed by python as a whole while js will use only \77
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return '\\' + hex(num)[1:], n + len_parsed
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return source[n + 1], n + 2
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#####TEST######
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if __name__ == '__main__':
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test = ('''
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''')
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t, d = remove_constants(test)
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print(t, d)
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