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133 lines
4 KiB
Python
133 lines
4 KiB
Python
#!/usr/bin/env python2
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# -*- coding: utf-8 -*-
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#
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# GuessIt - A library for guessing information from filenames
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# Copyright (c) 2011 Nicolas Wack <wackou@gmail.com>
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#
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# GuessIt is free software; you can redistribute it and/or modify it under
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# the terms of the Lesser GNU General Public License as published by
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# the Free Software Foundation; either version 3 of the License, or
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# (at your option) any later version.
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#
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# GuessIt is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# Lesser GNU General Public License for more details.
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#
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# You should have received a copy of the Lesser GNU General Public License
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# along with this program. If not, see <http://www.gnu.org/licenses/>.
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#
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from __future__ import unicode_literals
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import datetime
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import re
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def valid_year(year):
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return 1920 < year < datetime.date.today().year + 5
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def search_year(string):
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"""Looks for year patterns, and if found return the year and group span.
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Assumes there are sentinels at the beginning and end of the string that
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always allow matching a non-digit delimiting the date.
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Note this only looks for valid production years, that is between 1920
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and now + 5 years, so for instance 2000 would be returned as a valid
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year but 1492 would not.
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>>> search_year('in the year 2000...')
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(2000, (12, 16))
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>>> search_year('they arrived in 1492.')
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(None, None)
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"""
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match = re.search(r'[^0-9]([0-9]{4})[^0-9]', string)
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if match:
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year = int(match.group(1))
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if valid_year(year):
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return (year, match.span(1))
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return (None, None)
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def search_date(string):
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"""Looks for date patterns, and if found return the date and group span.
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Assumes there are sentinels at the beginning and end of the string that
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always allow matching a non-digit delimiting the date.
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>>> search_date('This happened on 2002-04-22.')
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(datetime.date(2002, 4, 22), (17, 27))
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>>> search_date('And this on 17-06-1998.')
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(datetime.date(1998, 6, 17), (12, 22))
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>>> search_date('no date in here')
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(None, None)
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"""
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dsep = r'[-/ \.]'
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date_rexps = [
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# 20010823
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r'[^0-9]' +
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r'(?P<year>[0-9]{4})' +
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r'(?P<month>[0-9]{2})' +
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r'(?P<day>[0-9]{2})' +
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r'[^0-9]',
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# 2001-08-23
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r'[^0-9]' +
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r'(?P<year>[0-9]{4})' + dsep +
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r'(?P<month>[0-9]{2})' + dsep +
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r'(?P<day>[0-9]{2})' +
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r'[^0-9]',
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# 23-08-2001
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r'[^0-9]' +
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r'(?P<day>[0-9]{2})' + dsep +
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r'(?P<month>[0-9]{2})' + dsep +
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r'(?P<year>[0-9]{4})' +
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r'[^0-9]',
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# 23-08-01
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r'[^0-9]' +
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r'(?P<day>[0-9]{2})' + dsep +
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r'(?P<month>[0-9]{2})' + dsep +
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r'(?P<year>[0-9]{2})' +
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r'[^0-9]',
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]
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for drexp in date_rexps:
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match = re.search(drexp, string)
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if match:
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d = match.groupdict()
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year, month, day = int(d['year']), int(d['month']), int(d['day'])
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# years specified as 2 digits should be adjusted here
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if year < 100:
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if year > (datetime.date.today().year % 100) + 5:
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year = 1900 + year
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else:
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year = 2000 + year
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date = None
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try:
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date = datetime.date(year, month, day)
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except ValueError:
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try:
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date = datetime.date(year, day, month)
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except ValueError:
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pass
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if date is None:
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continue
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# check date plausibility
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if not 1900 < date.year < datetime.date.today().year + 5:
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continue
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# looks like we have a valid date
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# note: span is [+1,-1] because we don't want to include the
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# non-digit char
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start, end = match.span()
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return (date, (start + 1, end - 1))
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return None, None
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